Convert high numbers to lower format

Question

How can I change high numbers to something like:

1,000 = 1K
1,250 = 1,2K
10,200 = 10,2K
102,000 = 102K
1,200,000 = 1,2M

Or something like that?

This is how I set the number:

textCell?.ll1.text = "\(String(thumb[indexPath.row].count))"
textCell?.ll2.text = "\(String(love[indexPath.row].count))"

Have a look at NSByteCountFormatter ... – Martin R Mar 07 '16 at 21:12 — Martin R, Mar 07 '16 at 21:12

score 1 · Answer 1 · answered Mar 07 '16 at 21:30

1

let formatter = NSByteCountFormatter()

That's it ;)

Examples:

let oneFormattedNumber = formatter.stringFromByteCount(1025000000000)
let formattedList = [1_000, 1_250, 10_200, 102_000, 1_200_000].map(formatter.stringFromByteCount)

answered Mar 07 '16 at 21:30

NiñoScript

4,523
2
27
33

score 0 · Answer 2 · answered Mar 07 '16 at 21:51

0

You can add this functionality as an extension to Int:

extension Int {
  func shortLiteralDescription() -> String {
        var factor = 0
        let tokens = ["","K", "M", "G","T","P"] //If you think you will need to express more, add them here
        var value = Double(self);
        while (value > 1000) {
            value /= 1000
            factor++
        }
        return "\(value)\(tokens[factor])"
    }
}

And then:

400200.shortLiteralDescription()   //400.2K
4000.shortLiteralDescription()     //4.0K

answered Mar 07 '16 at 21:51

Hugo Alonso

6,684
2
34
65

How do i use it in a function like this: `textCell?.ll1.text = "\(String(thumbEmoji[indexPath.row].count))"`? – Sibling Thor Mar 08 '16 at 07:23
textCell?.ll1.text = thumbEmoji[indexPath.row].count.shortLiteralDescription() – Hugo Alonso Mar 08 '16 at 13:47

Convert high numbers to lower format

2 Answers2

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