MVC - how does model binding work?

Question

I need to convert a string to an object, just like how model binding happens in MVC controllers.
so if I have a string of json like this:

{
  "name": "tom",
  "job": "developer",
  "projects": ["projectOne", "projectTwo"]
}

I could the convert it to this object:

public class Developer
{
  public string name {get; set;}
  public string job {get; set;}
  public string[] projects {get; set;}
}

something like this:

Developer developer = Convertor.TryConvert<Developer>(myJson);

so is there any library or function that can do this?

@JonasW could you post an answer so I can make it the right answer? — Mohsen Shakiba, Mar 08 '16 at 19:49
I guess I don't understand your question, you've tagged this question with MVC, why not just let MVC model bind it? — Erik Philips, Mar 08 '16 at 20:48
@MohsenShakiba sry for late answer.. I have posted a answer now. — Jonas W, Mar 08 '16 at 21:02
You do realize that the MVC framework does all this automatically? If the method you posting back to has a parameter `Developer model` then the `model` will be bound. — , Mar 08 '16 at 21:25

score 2 · Answer 1 · edited May 23 '17 at 11:45

2

Look here: How to Convert JSON object to Custom C# object?

Basically one of the answers is:

JavaScriptSerializer jss = new JavaScriptSerializer();
Developer user = jss.Deserialize<Developer>(jsonString);

edited May 23 '17 at 11:45

Community

1
1

answered Mar 08 '16 at 19:45

Slava Shpitalny

3,965
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really good answer but sadly I could only choose one correct answer. did vote you up though, thanks a lot – Mohsen Shakiba Mar 08 '16 at 21:05

score 2 · Accepted Answer · answered Mar 08 '16 at 21:00

You should check this out : http://www.newtonsoft.com/json

Sample :

string json = @"{
                   "name": "tom",
                   "job": "developer",
                   "projects": ["projectOne", "projectTwo"]
                 }";

Developer d = JsonConvert.DeserializeObject<Developer>(json);

MVC - how does model binding work?

2 Answers2