In this dataset I need to mark out application ID P-10900 because it is touched by 2 TeamMember. We can mark it out in form of a flag created as separate column.
I know it can be done using recursive CTE easily but not sure how to write the syntax.
TeamMember Status ApplicationID
NULL NW P-10900
John IR P-10900
John CO P-10900
Dick IR P-10900
Dick PA P-10900
NULL NW P-06700
John IR P-06700
John PA P-06700
NULL NW P-14600
Andre IR P-14600
This is an extension to the question asked here
Find which rows have different values for a given column in SQL
I am using MS SQL Server 2012
I am expecting output like this:
TeamMember Status ApplicationID Flag
NULL NW P-10900 Dup
John IR P-10900 Dup
John CO P-10900 Dup
Dick IR P-10900 Dup
Dick PA P-10900 Dup
NULL NW P-06700 Alike
John IR P-06700 Alike
John PA P-06700 Alike
NULL NW P-14600 Alike
Andre IR P-14600 Alike
Here is the Schema:
CREATE TABLE App
([TeamMember] varchar(5), [aStatus] varchar(2), [ApplicationID] varchar(7))
;
INSERT INTO App
([TeamMember], [aStatus], [ApplicationID])
VALUES
(NULL, 'NW', 'P-10900'),
('John', 'IR', 'P-10900'),
('John', 'CO', 'P-10900'),
('Dick', 'IR', 'P-10900'),
('Dick', 'PA', 'P-10900'),
(NULL, 'NW', 'P-06700'),
('John', 'IR', 'P-06700'),
('John', 'PA', 'P-06700'),
(NULL, 'NW', 'P-14600'),
('Andre', 'IR', 'P-14600')
;
This is what I attempted which ofcourse is not working:
WITH cte (applicationid, status, teammember)
AS (SELECT applicationid,
status,
teammember
FROM app
GROUP BY applicationid,
status,
teammember)
SELECT applicationid,
teammember,
status,
CASE
WHEN (SELECT DISTINCT CASE
WHEN Count(applicationid) > 1 THEN 'Alike'
ELSE 'Dup'
END
FROM cte B
WHERE B.teammember = A.teammember
GROUP BY B.teammember) = 'Alike' THEN 'Alike'
ELSE 'Dup'
END AS Flag
FROM cte A
ORDER BY applicationid