replacing a text with a pattern in java

Question

I have text like

String str = "<x>abc</x>";

and want to match against

<x>
   abc
</x>

i tried to do something like:

str = str.replaceAll(">",">\\\\w*");
str = str.replaceAll("<","\\\\w*<");

Pattern pattern = Pattern.compile(str);

how the value of str in the compile is actually

\w*<x>\w*abc\w*</x>\w*

i was expecting

\\w*<x>\\w*abc\\w*</x>\\w*

If you are working with backslashes in regex, keep in mind they can either escape something in the python string literal, or in the regular expression Itself. To get an actual backslash either use raw strings (preferred) `r"\\w*<"` Or double-escape them `"\\\\w*<"` — Felk, Mar 08 '16 at 23:00

score 0 · Answer 1 · edited Mar 09 '16 at 05:15

0

I have to use eight(8) \ characters (i.e. \\\\\\\\) in order to get two(2) in the output. It's a little strange but works.

edited Mar 09 '16 at 05:15

William Price

answered Mar 08 '16 at 23:09

Vik

1 Answers1