Printing an int array

Question

I can't come up with an idea on why the array is printing out the int's in order instead of the order that they're put in the array.

int[] array = {1, 4, 0, 3, 2};
for(int i : array){
        System.out.println(array[i]);
}

Is there any explanation of this?

Thanks in advance!

the `i` does not represent the index, it´s rather a value returned by the `Iterator` and the current element of it — SomeJavaGuy, Mar 09 '16 at 08:53

Eran · Accepted Answer · 2016-03-09T08:53:48.350

4

You should be printing the loop's variable :

for(int i : array){
    System.out.println(i);
}

If you print array[i] instead of i, you get 4 instead of 1 as the first printed element, since array[1] == 4.

Your code would be correct if you were using the traditional for loop, which iterates over the indices of the array :

for(int i = 0; i < array.length; i++){
    System.out.println(array[i]);
}

edited Mar 09 '16 at 08:53

answered Mar 09 '16 at 08:51

Eran

1

you beat me to speed. Your int i here is not equivalent to an index. It's your current integer value being read. – Alex Mar 09 '16 at 08:51
I just came in this, and he posted. – user3437460 Mar 09 '16 at 08:53

1 Answers1