Scala, call the "self" object in arguments

Question

I'm actually running this code in Scala

val obj2 = obj1.method1()
val result = obj2.method2(obj2.name)

I would know if is somehow possible use the obj2 in a argument concatenating the calls, to clarify I would write something like

val result = obj1.method1().method2(_.name)

where _ is referring to the object previously computed. I don't know if it's possible, it's just a style question, the first code works fine

@manub, I have placed the underscore because in Scala it's often use for this kind of thinks, and I would simply clarify what I would do, but actually is not the correct syntax and doesn't work, so I would know if could be possible obtain something like that — Cattani Simone, Mar 09 '16 at 17:20

score 3 · Answer 1 · answered Mar 09 '16 at 18:15

3

We can do this (borrowing into name from http://combinators.info/):

implicit class Into[A](x: A) {
  def into(f: A => B) = f(x)
}

obj1.method1().into { x => x.method2(x.name) }

answered Mar 09 '16 at 18:15

Alexey Romanov

thanks, I think that it is the solution more close to what I want, I hoped for a "prettier" way, but I don't thinks is possible – Cattani Simone Mar 09 '16 at 18:19
If that's what you want, you can do it simpler: `Some(obj1).map(_.method1).map { x => x.method2(x.name) }.get` – Dima Mar 09 '16 at 22:48
‛into‛ as defined here is generally named ‛|>‛ aka the "forward pipe operator" – Régis Jean-Gilles Mar 10 '16 at 07:35

1 Answers1