how to sort array os objects which is alphanumeric

Question

I am trying to sort array as shown of objects which contains alphanumeric value

[
{ bayid="A1",  status=0}, 
{ bayid="A7",  status=0}, 
{ bayid="A6",  status=0}, 
{ bayid="A5",  status=0}
]

i am using the .sort method which is shown below

var sortedArray = modifiedStatusArray.sort(function(a, b) {
                return +b.bayid > +a.bayid;
            });

but not sure how to sort and get the output as shown below

[

{ bayid="A7",  status=0}, 
{ bayid="A6",  status=0}, 
{ bayid="A5",  status=0},
{ bayid="A1",  status=0}
]

please help

That sort method won't work for any data, let alone alphanumeric data. A sort callback isn't supposed to return a boolean. — nnnnnn, Mar 10 '16 at 00:13
Try using just `.sort(function(a,b){ return b.bayid.match(/\d+/) - a.bayid.match(/\d+/) })` — , Mar 10 '16 at 00:19

score 4 · Answer 1 · edited May 23 '17 at 11:50

I notice that you have a problem with your objects, the definition of you variable should be as follows:

var data = [
    { bayid: "A1",  status: 0}, 
    { bayid: "A7",  status: 0}, 
    { bayid: "A6",  status: 0},
    { bayid: "A5",  status: 0}
];

You can use the sort function:

var sorted = data.sort(function(a, b){
    if( a.bayid === b.bayid ){
      return 0;
    } else if ( a.bayid < b.bayid ) {
      return 1;
    } else {
      return -1;
    }
});
console.log( sorted );

The sort function takes a function as an argument, that function behaves as a comparison function (optional argument), that sort the values of the array based on the returned value of the function.

From the spec:

The array elements are sorted according to the return value of the compare function

If the returned value is:

less than 0, sort a to a lower index than b.
0 (equal to zero), leave a and b unchanged with respect to each other.
greater than 0, sort b to a lower index than a.

More information from the spec.

There is a very similar question on the site as well it might be helpful, if you search on the site before creating a new question.

According to W3, Array.sort expects an integer return value (-1, 0, 1), not a boolean. — Comptonburger, Mar 10 '16 at 00:15
your order is `[ { bayid: 'A1', status: 0 }, { bayid: 'A5', status: 0 }, { bayid: 'A6', status: 0 }, { bayid: 'A7', status: 0 } ]` — isvforall, Mar 10 '16 at 00:29

isvforall · Answer 2 · 2016-03-10T00:24:22.587

1

Your sort function should return 1, -1 or 0

var sortedArray = modifiedStatusArray.sort(function(a, b) {
    return a.bayid < b.bayid ? 1 : a.bayid > b.bayid ? -1 : 0;
});

edited Mar 10 '16 at 00:24

answered Mar 10 '16 at 00:16

isvforall

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I think the sorting might be backwards here. If a < b then it should return negative. – Comptonburger Mar 10 '16 at 00:19
@Comptonburger try it yourself, it's working, `a < b` should return `1` – isvforall Mar 10 '16 at 00:29

how to sort array os objects which is alphanumeric

2 Answers2