How do you flip a specific bit in a Java primitive byte?

Question

I have never used bytes in Java before, so I am unfamiliar with the sytnax for manipulating bytes and bits. I searched how to do this task, but I can't find a simple solution.

I have a byte b. b has eight bits. I would like to flip the ith bit of b to its negation (0 -> 1, 1 -> 0). How do I do this?

Possible duplicate of [Set specific bit in byte](http://stackoverflow.com/questions/4674006/set-specific-bit-in-byte) — Burkhard, Mar 10 '16 at 06:04
I don't understand this answer's notation of what i and bit stand for. — maxematician, Mar 10 '16 at 06:06

score 1 · Answer 1 · answered Mar 10 '16 at 06:07

I think this will work:

byte b = 0; // initial val ...0000000
final int theNumberofTheBitToFlip = 2; // bit to flip
b = (byte) (b ^ (1 << theNumberofTheBitToFlip));
System.out.println(b); // result ...0000100 = 8
b = (byte) (b ^ (1 << theNumberofTheBitToFlip));
System.out.println(b);// result ...0000000 = 8

score 0 · Answer 2 · edited Mar 10 '16 at 06:16

0

Try this

int i=3; 
b = (byte) (b ^ (1 << i));

edited Mar 10 '16 at 06:16

swiftBoy

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answered Mar 10 '16 at 06:06

Harsha_rai

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How do you flip a specific bit in a Java primitive byte?

2 Answers2