how to cast int [] data type to byte [] data type

Question

I have the following error in compiler

return  ans;
                ^
  required: byte[]
  found:    int[]

I have this method in which i want to return a type of byte . Can anyone tell me how can i cast ans to make it compatible with me method type

public  byte[]  element(int m) {
    //if (q!= a.length)
    // throw new Exception("Array length does not equal k");
    int f;
    int q;
    int[] t;

    this.first = f;
    this.second = q;
    this.data = new int[q];

    for (int i = 0; i < t.length; ++i) {
        this.data[i] = t[i];
    }

    // if (!this.IsValid())
    //  throw new Exception("Bad value from array");


    int ans[] = new int[this.second];

    int a = this.first;
    int b = this.second;
    int x = (choose(this.first,this.second) - 1) - m; // x is the "dual" of m

    for (int i = 0; i < this.second; ++i) {
        ans[i] = largestV(a, b, x); // largest value v, where v < a and vCb < x
        x = x - choose(ans[i], b);
        a = ans[i];
        b = b - 1;
    }

    for (int i = 0; i < this.second; ++i) { 
        ans[i] = (first-1) - ans[i];
        return  ans;
    }
}

Note: i want it to return type of byte not int but i am trying to cast ans but without success .

Possible duplicate of [How to convert int\[\] to byte\[\]](http://stackoverflow.com/questions/1086054/how-to-convert-int-to-byte) — Harmelodic, Mar 10 '16 at 17:33
Why create it as an int[] if you want a byte[]? Just create it as a byte and do your casting in the assignment "ans[i] = (byte) largestV(...)". — BarrySW19, Mar 10 '16 at 17:35

score 0 · Answer 1 · answered Mar 10 '16 at 17:25

You have to change int[] ans to Byte[] ans, you are trying to return an int array, but you have to return your byte array

int f;
   int q;
  int [] t;

    this.first = f;
    this.second = q;
    this.data = new int[q];
    for (int i = 0; i < t.length; ++i)
      this.data[i] = t[i];

   // if (!this.IsValid())
    //  throw new Exception("Bad value from array");


        byte ans []= new byte[this.second];

        int a = this.first;
        int b = this.second;
        int x = (choose(this.first,this.second) - 1) - m; // x is the "dual" of m

        for (int i = 0; i < this.second; ++i) {
            ans[i]= largestV(a, b, x); // largest value v, where v < a and vCb < x
            x = x - choose(ans[i], b);
            a = ans[i];
            b = b - 1;
        }

        for (int i = 0; i < this.second; ++i)

            ans[i] = (first-1) - ans[i];

        return  ans;
    }

i tried that before i posted my question and is not working because all the code below byte ans []= new byte[this.second]; must be casted into byte then — john smith, Mar 10 '16 at 17:54
@johnsmit then that's what you'll have to do. You can cast `int` to `byte` but not `int[]` to `byte[]`. — Louis Wasserman, Mar 10 '16 at 17:56

score 0 · Answer 2 · answered Mar 10 '16 at 18:18

Dunno why you would wanna to work on int and return a byte. Dat aside, You can create a new byte array of the same size as ans and do this in the last loop

for (int i = 0; i < this.second; ++i)
{ 
    ans[i] = (first-1) - ans[i]);
    ans_byte_version[i] =  (byte) ((first-1) - ans[i]);
}
return ans_byte_version;

However it'd be better if you tell us what are you trying to do. Why have you declared int when you want byte in the first place.

how to cast int [] data type to byte [] data type

2 Answers2