regexp get content type boundary

Question

How to get the boundary in this header?

$header = 'Content-Type: multipart/report; report-type=delivery-status;'."\n"
.'    boundary="9B095B5ADSN=_01D16F24CC6015F600AB1926COL004?MC5F18.ho"';

preg_match('/Content-Type:(.*)boundary="([^\"]+)"/i', $header, $match);
print_r($match);

output

9B095B5ADSN=_01D16F24CC6015F600AB1926COL004?MC5F18.ho

Use the `s` modifier. Demo: https://eval.in/535591 – chris85 Mar 13 '16 at 01:20 — chris85, Mar 13 '16 at 01:20

score 1 · Accepted Answer · answered Mar 13 '16 at 01:20

1

Try this

preg_match('/boundary="(.*?)"/i', $header, $match);

or

preg_match('/Content-Type:(.*)\n*\s*boundary="([^\"]+)"/i', $header, $match);

Output

9B095B5ADSN=_01D16F24CC6015F600AB1926COL004?MC5F18.ho

answered Mar 13 '16 at 01:20

Tim007

2,557
1
11
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rm_beginners · Answer 2 · 2016-03-13T01:29:23.313

1

preg_match('/boundary=(.*)/', $header, $match);

edited Mar 13 '16 at 01:29

answered Mar 13 '16 at 01:26

rm_beginners

164
5

regexp get content type boundary

2 Answers2