Difference in hours between 2 particular days - PHP

Question

I have two date objects say 10/01/2016 00:00:00 to 18/01/2016 08:00:00. I want to check whether these 2 dates lies between friday 12 AM to Sunday 12 Am then how to find difference in hours ?

PHP code -

$t1 = StrToTime($date2);
$t2 = StrToTime($date1);
$diff = $t1-$t2;

$hours = abs($diff / ( 60 * 60 ));

I am badly stuck in this. Please someone help.

Thanks in Advance.

@PraveenKumar [It's not *required*, but it does look way prettier in lowercase letters](https://eval.in/536130). — h2ooooooo, Mar 14 '16 at 11:09
Not necessary, but you still shouldn't RandOMizE CApiTalIZAtioN... — deceze, Mar 14 '16 at 11:10
Ha ha okay @deceze ... `:)` But the code looks alright for me. What does the two date variables contain? — Praveen Kumar Purushothaman, Mar 14 '16 at 11:11
@SearchAndResQ That's the same code the OP has given, which is not working. — Praveen Kumar Purushothaman, Mar 14 '16 at 11:12

Gerald Schneider · Answer 1 · 2016-03-14T11:31:54.873

If I understand your question correctly you want to test if the date is either a friday or a saturday, with no relevance how far they are away from each other.

You can use the format() function of the DateTime object to get the weekday of the date, then test if it is a friday (5) or a saturday (6):

$t1 = DateTime::createFromFormat("d/m/Y H:i:s", "10/01/2016 00:00:00");
$t2 = DateTime::createFromFormat("d/m/Y H:i:s", "18/01/2016 08:00:00");

function testDate($date) {
    $d = $date->format("N");
    if ($d == 5) return true;
    if ($d == 6) return true;
    return false;
}

$d1 = testDate($t1);
$d2 = testDate($t2);

var_dump($d1, $d2);

// Result:
// bool(false)
// bool(false)

Then you can use the DateTime::diff() function to get the difference:

$diff = $t1->diff($t2);
var_dump($diff);

Result:

object(DateInterval)#3 (15) {
  ["y"]=>
  int(0)
  ["m"]=>
  int(0)
  ["d"]=>
  int(8)
  ["h"]=>
  int(8)
  ["i"]=>
  int(0)
  ["s"]=>
  int(0)
  ["weekday"]=>
  int(0)
  ["weekday_behavior"]=>
  int(0)
  ["first_last_day_of"]=>
  int(0)
  ["invert"]=>
  int(0)
  ["days"]=>
  int(8)
  ["special_type"]=>
  int(0)
  ["special_amount"]=>
  int(0)
  ["have_weekday_relative"]=>
  int(0)
  ["have_special_relative"]=>
  int(0)
}

So, 8 days ($diff['days']) and 8 hours ($diff['h'])

suppose my two date is 13/03/2016 11 Am to 14/03/2016 12 AM so between Friday 12Am To Sunday 12 AM i get 1 hours result ... — Jayesh Barot, Mar 14 '16 at 11:43

JP. Aulet · Answer 2 · 2016-03-14T12:31:13.130

You can use:

$date1 = "2016-08-14 00:00:00"; //more higger day
$date2 = "2016-08-13 00:00:00";    
$diff = abs(strtotime($date2) - strtotime($date1)); 

$years   = floor($diff / (365*60*60*24)); 
$months  = floor(($diff - $years * 365*60*60*24) / (30*60*60*24)); 
$days    = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));    
$hours   = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24 - $days*60*60*24)/ (60*60));     
$minuts  = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24 - $days*60*60*24 - $hours*60*60)/ 60);     
$seconds = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24 - $days*60*60*24 - $hours*60*60 - $minuts*60)); 

printf("%d years, %d months, %d days, %d hours, %d minuts\n, %d seconds\n", $years, $months, $days, $hours, $minuts, $seconds);

Output: 0 years, 0 months, 1 days, 0 hours, 0 minuts , 0 seconds

Now, you can do:

$date1 = "2016-08-14 00:00:00"; //more higger day
$date2 = "2016-08-13 00:00:00";    
$diff = abs(strtotime($date2) - strtotime($date1)); 

$years   = floor($diff / (365*60*60*24)); 
$months  = floor(($diff - $years * 365*60*60*24) / (30*60*60*24)); 
$days    = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));    
$hours   = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24 - $days*60*60*24)/ (60*60));   

echo "Totals hours: ".($days*24 + $hours);

Returns 24 (and you can multiply the years, months and so on)

suppose my two date is 13/03/2016 11 Am to 14/03/2016 12 AM so between Friday 12Am To Sunday 12 AM i get 1 hours result — Jayesh Barot, Mar 14 '16 at 12:18

Difference in hours between 2 particular days - PHP

2 Answers2