Unexpected thread executing

Question

Running the code:

Thread tt = new Thread(new Runnable() {

            @Override
            public void run() {
                System.out.println(Thread.currentThread().getName());
            }
        });
System.out.println(tt.getName());
tt.run();

I would expect to get:

Thread-0
Thread-0

But instead I get:

Thread-0
main

Why is that?

Call `start()` on Threads, not `run()`. – Hovercraft Full Of Eels Mar 14 '16 at 15:50 — Hovercraft Full Of Eels, Mar 14 '16 at 15:50
Yep, sorry for being stupid :-( – Johnny Mar 14 '16 at 15:51 — Johnny, Mar 14 '16 at 15:51

score 0 · Answer 1 · answered Mar 14 '16 at 15:51

0

Your Thread's run method doesn't do anything. The Runnable's run method calls println, but in your code it's never run. Call start() on the thread not run()

answered Mar 14 '16 at 15:51

Hovercraft Full Of Eels

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Unexpected thread executing

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