Sort tuple by first then second then third

Question

I have the following tuple:

[[278, 388, 0.95434654], [279, 388, 0.98770386], [280, 388, 0.960356], [442, 388, 0.98245245], [443, 388, 0.96607447], [278, 389, 0.95714802], [279, 389, 0.98451048], [280, 389, 0.95131117], [442, 389, 0.98007435], [443, 389, 0.95733315]]

I would like to sort it by first then second then third.

I tried the following but it only sorts by first:

def getKey(item):
    return item[0]

all_matches_tuple = sorted(all_matches_tuple, key=getKey)

Note: Those aren't tuples. Those are lists. You have a list of lists. — Andy, Mar 14 '16 at 18:44
I corrected the spelling of `tuple`, but you really have lists here. — Martijn Pieters, Mar 14 '16 at 18:46

Martijn Pieters · Answer 1 · 2016-03-14T18:58:09.037

Just sort without a key, the default is to sort tuples in lexicographical order:

sorted(all_matches_tuple)

Demo:

>>> sorted([[278, 388, 0.95434654], [279, 388, 0.98770386], [280, 388, 0.960356], [442, 388, 0.98245245], [443, 388, 0.96607447], [278, 389, 0.95714802], [279, 389, 0.98451048], [280, 389, 0.95131117], [442, 389, 0.98007435], [443, 389, 0.95733315]])
[[278, 388, 0.95434654], [278, 389, 0.95714802], [279, 388, 0.98770386], [279, 389, 0.98451048], [280, 388, 0.960356], [280, 389, 0.95131117], [442, 388, 0.98245245], [442, 389, 0.98007435], [443, 388, 0.96607447], [443, 389, 0.95733315]]

but note that your sample doesn't actually contain any values where both the first and second number are equal.

Sort tuple by first then second then third

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