Converting date format in PHP to Y-m-d H:i:s fails

Question

I have date in format like 23:44 01.03.2016, I need to format it to: Y-m-d H:i:s.

Here is what I try:

$article_date = strtotime($date);
$article_date2 = date('Y-m-d H:i:s',$article_date);

where $date is 23:44 01.03.2016.

The code returns 1970-01-01 01:00:00. I've also tried different dates, similar outcome. How to solve this?

Thanks!

It seems to me your first assignment ($article_date = strtotime($date);) is failing and then $article_date is null. Then the second one reads it like UNIX standard time. — Ed de Almeida, Mar 15 '16 at 11:58
Maybe you should change the name of $date. It is not good to have a variable whose name is a function name. It may lead to confusion sometimes. — Ed de Almeida, Mar 15 '16 at 12:00
Echo $date gives 23:44 01.03.2016 and it seems that strtotime() is failing. How to fix it? — dreamPr, Mar 15 '16 at 12:05

Sachin · Accepted Answer · 2016-03-16T07:48:34.843

0

Maybe you can try this:

$date = new DateTime('23:44 01.03.2016');
echo $date->format('Y-m-d H:i:s');

for more details on the object DateTime check this

edited Mar 16 '16 at 07:48

answered Mar 15 '16 at 11:59

Sachin

Second parameter is timestamp – dreamPr Mar 15 '16 at 12:28
is the problem solved ? – Sachin Mar 15 '16 at 15:16
No, problem is not solved yet – dreamPr Mar 15 '16 at 15:19
did u tried the above one. – Sachin Mar 15 '16 at 15:28
This works: https://eval.in/536835 – Glavić Mar 15 '16 at 15:29
Now its fine, problem is solved. Thank You very much! – dreamPr Mar 15 '16 at 15:43
While this answer is probably correct and useful, it is preferred if you [include some explanation along with it](http://meta.stackexchange.com/q/114762/159034) to explain how it helps to solve the problem. This becomes especially useful in the future, if there is a change (possibly unrelated) that causes it to stop working and users need to understand how it once worked. Thanks! – Hatchet Mar 15 '16 at 18:16

1 Answers1