My question is different with the typical one. Assume we have,
X = ['123', '456', '789']
And, we want to find whether another list is in X with exact same order. For example,
A = ['123', '456']
# should return True since A in X with same order
B = ['456', '123']
# should return False since elements in B are not in same order with X
C = ['123', '789']
# should return False since elements in C are not adjacent in X
Can anyone give me any idea?
Python 2:
def is_a_in_x(A, X):
for i in xrange(len(X) - len(A) + 1):
if A == X[i:i+len(A)]: return True
return False
Python 3:
def is_a_in_x(A, X):
for i in range(len(X) - len(A) + 1):
if A == X[i:i+len(A)]: return True
return False
def foo(your_list, your_main_list):
list_len = len(your_list)
for i, item in enumerate(your_list):
if your_main_list[i] == item:
if i + 1 == list_len:
return True
else:
return False
One possible solution if your numbers are always three digit:
x = ['123', '456', '789']
A = ['123', '456']
''.join(A) in ''.join(x)
B = ['456', '123']
''.join(B) in ''.join(x)
C = ['123', '789']
''.join(C) in ''.join(x)
Although, prone to bugs for example:
D = ['1', '23']
''.join(D) in ''.join(x)
outputs True
