jquery replace not working for '['

Asked Mar 17 '16 at 06:17

Active Mar 17 '16 at 06:17

Viewed 17 times

I want to replace '[0' with '[' and '[1' with '['

var sign ='[[1,17.5,24],[0,17.5,25],[0,17.5,26],[0,17.5,31],,,,[0,280.5,47],[0,282.5,49]]';
   sign.replace('[0,','[').replace('[1,', '[')
      alert(sign)

but same value is there

Expected:[[17.5,24],[17.5,25],[17.5,26],[17.5,31],[280.5,47],[282.5,49]]

Please help

asked Mar 17 '16 at 06:17

aparna chowdary

1

You have to assign the value back - `sign = sign.replace('[0,','[').replace('[1,', '[')` – Arun P Johny Mar 17 '16 at 06:18
@ArunPJohny thanks for correction but it replaces first two values [[17.5,24],[17.5,25],[0,17.5,26],[0,17.5,31],[0,280.5,47],[0,282.5,49]] rest remains same – aparna chowdary Mar 17 '16 at 06:24
http://stackoverflow.com/questions/6064956/replace-all-occurrences-in-a-string – Arun P Johny Mar 17 '16 at 06:29
2

`sign.replace(/\[0,/g,'[').replace(/\[1,/g, '[')` – Arun P Johny Mar 17 '16 at 06:30
Thanks it worked for me.. – aparna chowdary Mar 17 '16 at 06:35

jquery replace not working for '['

0 Answers0