How I can change the particular URL into the sub URL

Question

I have the following URL

http://androidexample.com/Create_A_Simple_Listview_-_Android_Example/index.php?view=article_discription&aid=65&aaid=90

I want to break this into below URL-

www.androidexample.com

How can write code for this?

why you want to break....as webservice wont work without parameter... — Iamat8, Mar 17 '16 at 14:14

score 1 · Answer 1 · answered Mar 17 '16 at 14:19

1

Use:

String uriStr = "http://androidexample.com/Create_A_Simple_Listview_-_Android_Example/index.php?view=article_discription&aid=65&aaid=90";
String host = new URI(uriStr).getHost();

answered Mar 17 '16 at 14:19

Alexey

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score 1 · Answer 2 · answered Mar 18 '16 at 11:17

1

URI uri = new URI("http://androidexample.com/Create_A_Simple_Listview_-_Android_Example/index.php?view=article_discription&aid=65&aaid=90");
    System.out.println("URI      : " + uri);
    System.out.println(uri.getHost());

answered Mar 18 '16 at 11:17

Bajirao Shinde

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score 0 · Answer 3 · edited May 23 '17 at 12:07

0

You can look for the // and for the first / in the url.

e.g.

int slashslash = url.indexOf("//") + 2;
domain = url.substring(slashslash, url.indexOf('/', slashslash));

It was answered here: What is the fastest way to get the domain/host name from a URL?

edited May 23 '17 at 12:07

Community

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answered Mar 17 '16 at 14:15

Someone

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Ravi Vaghela · Answer 4 · 2016-03-18T11:14:41.930

You have to get domain name of particular URL. just pass your URL in below code you can get domain or sub URL.

String url="http://androidexample.com/Create_A_Simple_Listview_-_Android_Example/index.php?view=article_discription&aid=65&aaid=90";
String subUrl = getDomainName(url);


public static String getDomainName(String url) throws URISyntaxException {
URI uri = new URI(url);
String domain = uri.getHost();
return domain.startsWith("www.") ? domain.substring(4) : domain;
}

How I can change the particular URL into the sub URL

4 Answers4