Java calculator debugging

Question

I am learning Java by debugging programs from various tutorials. At a moment I am fixing this calculator: http://www.dreamincode.net/forums/topic/321933-creating-a-calculator-using-jframe/
If you press "1/1" it displays "1.0" instead of "1". I am leaning towards

if (abs(result-round(result)) < 0.000000001){(int)(result)}

What would be an appropriate way to fix this glitch? Thank you in advance,

this may help http://stackoverflow.com/questions/14204905/java-how-to-remove-trailing-zeros-from-a-double — Madhawa Priyashantha, Mar 18 '16 at 02:33
`(int)(result)` is meaningless. Do you mean `result=(int)(result);`? — MikeCAT, Mar 18 '16 at 02:33
Yes, I mean result=(int)(result);. Is there a better way to achieve this? I am trying to learn good coding practices. — Stepan, Mar 18 '16 at 02:37
@StepanLenevich if you do `(int)(result);` you don't get 1.5 for 3/2 — Madhawa Priyashantha, Mar 18 '16 at 02:38
That is why I am checking for if (abs(result-round(result)) < 0.000000001) — Stepan, Mar 18 '16 at 02:39

score 1 · Accepted Answer · answered Mar 18 '16 at 03:01

1

I think you are close to what you want, but this code is probably the more correct way to do it:

if (abs(result-round(result)) < 0.000000001){(int)Math.round(result);}

answered Mar 18 '16 at 03:01

Trey50Daniel

1 Answers1