Java: How to print corresponding alphabets till a number entered by user?

Question

I'm a beginner in Java and I'm trying to find out how to create a segment of code that can allow a user to enter a number between 1 and 26, and have the corresponding number of sequential letters to appear?

For example, if the user enters 3 then the computer would output a, b, c

Thank you in advance.

Update: I wrote the following code but there is an error message stating that the i in the integer conversion part is a duplicate of a local variable?

In another method, the user inputs the number between 1 and 26 and I'm reading that input as the String variable "num".

public String getChar (int i){
  String num;  
  String text = mini1Num.getText();
  
  Integer i = Integer.valueOf(text);

  return i > 0 && i < 27 ? String.valueOf((char)(i + 'A' - 1)) : null;


 }

What am I doing wrong?

Possible duplicate of [Converting number to letter](http://stackoverflow.com/questions/10813154/converting-number-to-letter) — Alexei - check Codidact, Mar 21 '16 at 12:49
Try a String array and a loop, then get back to us with some code. — heniv181, Mar 21 '16 at 12:49

score 3 · Accepted Answer · 2016-03-21T14:52:04.147

int n <---- number entered by user
for(int i=97;i<(97+n);i++)
    System.out.print((char)i+" ");

This gives you what you need.

EDIT
The error in your code lies in the return statement.

return i > 0 && i < 27 ? String.valueOf((char)(i + 'A' - 1)) : null;

The value of (i + 'A' -1) is of type char. So the type casting basically takes the form of (char) char instead of (char) int, which is problematic.

Java: How to print corresponding alphabets till a number entered by user?

1 Answers1