This output should be true.but it give false always.
Number.isInteger(parseFloat('134965.83') / parseFloat('0.01'))
This output should be true.but it give false always.
Number.isInteger(parseFloat('134965.83') / parseFloat('0.01'))
Floating point arithmetic in Javascript is broken and in general as well.
It has nothing to do with division, it will return false if you don't do division since you are checking float value.
Number.isInteger(parseFloat('134965.83') / parseFloat('0.01'))
translates to Number.isInteger(13496582.999999998)
-> false
Check these examples.
Number.isInteger(parseFloat('134965.83') )// outputs false without division
As per the spec
If Type(argument) is not Number, return false.
If floor(abs(argument)) ≠ abs(argument), return false.
This happens because the outcome of the division is not an integer but something like 13496582.999999998
.
Some floating numbers require a very small precision that is limited by the data type used. For example, the number 1/3
can never be expressed entirely as 0.333333333333
because there is a limitation to the data type size. Therefore there will always be a tiny rounding error involved in floating operations.
Edit: In response to the comment asking for a recommendation on how to deal eith this, actually there are several possibilities. It depends on the context and on accuracy required.
In short, to overcome this use a very small constant Number.EPSILON (see also this) and use it in comparisons. Disclaimer: this is just a quick example, read extensively the implications on the links provided.
var myIsInteger = function(n) {
return (n % 1) > Number.EPSILON
};
We effectively check that the residual of the division with 1 is within the constant.
parseFloat('134965.83') / parseFloat('0.01') = 13496582.999999998
And when Number.isInteger(13496582.999999998) will always return false