An exception in splitting

Question

I am trying to split an IP address by ".". But code is generating an exception.

Exception Message : "Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 0
    at decimaltobinary.DecimalToBinary.main".

Help me to solve. Here is my Code.

 String[] ipAddresses=IP.split(".");
 String ip1=ipAddresses[0];
 String ip2=ipAddresses[1];
 String ip3=ipAddresses[2];
 String ip4=ipAddresses[3];

This means that there are no elements in your array. Print the original value of IP before spliting. — Stultuske, Mar 22 '16 at 14:18
i think you should use `'.'` instead of `"."` since you should split by a char, not a string — TobiasR., Mar 22 '16 at 14:20

score 3 · Answer 1 · edited Mar 22 '16 at 14:26

3

. is special character in regular expressions. Try:

IP.split("\\.");

edited Mar 22 '16 at 14:26

Buhake Sindi

answered Mar 22 '16 at 14:20

Gregory Prescott

score 1 · Answer 2 · answered Mar 22 '16 at 14:22

1

In a regex, the token . means to match on any character. If you want to match the character literal ., you need to split on the regex \..

This means that the actual String must represent \. so you'll have to do .split("\\.").

answered Mar 22 '16 at 14:22

CAD97

score 0 · Answer 3 · answered Mar 22 '16 at 14:23

0

try with (\\.) ie String[] ipAddresses=IP.split("\\.") that will give you

String[] ipAddresses=IP.split("\\.");
 String ip1=ipAddresses[0];
 String ip2=ipAddresses[1];
 String ip3=ipAddresses[2];
 String ip4=ipAddresses[3];

it should be work.

answered Mar 22 '16 at 14:23

Toukea Tatsi

3 Answers3