How to send one more request when failed for once with python-requests?

Question

I am writing a url fetcher. When I send a request like:

import requests
response = requests.get("http://example.com")

Sometimes an error like this occurs:

ConnectionError: ('Connection aborted.', BadStatusLine(""''''"))

But when I try one more time, it fixes. So I would like to send one more time when such an error occurs again. How can I do that? Thank you in advance!

You could increase the [maximum retry count from the default](http://stackoverflow.com/questions/15431044/can-i-set-max-retries-for-requests-request). — Martijn Pieters, Mar 22 '16 at 18:45
You might be better using a try/except and retrying after catching the error — Padraic Cunningham, Mar 22 '16 at 18:49

score 1 · Accepted Answer · answered Mar 22 '16 at 19:09

1

Repeat the request again when the exception is raised.

import requests

url = "http://example.com"

try:
    response = requests.get(url)
except requests.exception.ConnectionError:
    response = requests.get(url)

answered Mar 22 '16 at 19:09

Dušan Maďar

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How to send one more request when failed for once with python-requests?

1 Answers1