Parse error on Assignment operator

Question

I'm new in PHP, so may be I'm wrong (so don't down-vote me) because I'm here for learning.

I'm trying to understand Parse error on Assignment operator.

Example:

<?php
$additon = 2 + 4;
echo "Perform addition: 2 + 4 = " $addition;
?>

Why do I get this error?

Parse error: syntax error, unexpected '$addition' (T_VARIABLE), expecting ',' or ';'

And, why the sum of 6 not showing?

you have forgotten the string concatenation in the echo statement — Ankanna, Mar 26 '16 at 07:12
Thanks, but still `Undefined variable` error showing and the result not showing. — Aariba, Mar 26 '16 at 07:13
You have spelled `addition` wrong in one instance, that is why the undefined variable. — Rasclatt, Mar 26 '16 at 07:13
at the time of declaration you forgot the `i` after `o` in the spelling `additon` check taht once — Ankanna, Mar 26 '16 at 07:17

Indrasis Datta · Accepted Answer · 2016-03-26T07:14:07.020

1

You just need to concatenate these two using a dot.

$addition = 2 + 4;
echo "Perform addition: 2 + 4 = ". $addition;

Hope this helps.

edited Mar 26 '16 at 07:14

answered Mar 26 '16 at 07:10

Indrasis Datta

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thanks, but `Undefined variable` showing and the result not showing. – Aariba Mar 26 '16 at 07:12
1

Please check your variables. You have declared additon on top instead of addition. :) – Indrasis Datta Mar 26 '16 at 07:13
Thanks, works. But why use `concatenate` ? – Aariba Mar 26 '16 at 07:15
That's because "Perform addition: 2 + 4 = " is a string and $addition is a variable. When you're printing these two, they need to be concatenated. – Indrasis Datta Mar 26 '16 at 07:33

score 0 · Answer 2 · answered Mar 26 '16 at 07:31

With concatenation, the period operator has a higher precedence than both the addition and ternary operators, and so parentheses must be used for the correct behaviour.

<?php
  echo 'Sum: ' . (1 + 2);
?>

From http://php.net/manual/en/function.echo.php

Hope it helps to understand about concatenation.

Parse error on Assignment operator

2 Answers2