Having issues with C using float and printf

Question

I'm trying to run some basic code in C to declare 2 float variables, and then divide them and put that value in the 3rd variable. After this I print all 3.

#include <stdio.h>
int main ()
{
  /* variable definition: */
  float a, b, c; 
  /* variable initialization */
  a = 1.2;
  b = 2.7;  
  c = a / b;
  printf("Floats (a,b) and quotient (c) are : %d,%d,%d \n", a,b,c);  
   return 0;
}

I'm using the online compiler "www.ideone.com" to compile and run the code, and this is the result I'm getting:

Success time: 0 memory: 2156 signal:0

Floats (a,b) and quotient (c) are : 1073741824,1072902963,-1610612736

Can anyone see if perhaps I made a mistake in the code? It's for a class and everything worked fine for every step of directions until I changed from int to float.

http://www.cplusplus.com/reference/cstdio/printf/ %d is for integers, %f for floats. — OldProgrammer, Mar 27 '16 at 18:26

score 1 · Accepted Answer · answered Mar 27 '16 at 18:26

1

You want to print floats, thus change this:

printf("Floats (a,b) and quotient (c) are : %d,%d,%d \n", a,b,c);

to this:

printf("Floats (a,b) and quotient (c) are : %f,%f,%f \n", a,b,c);

For more, check the ref.

answered Mar 27 '16 at 18:26

gsamaras

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Thanks that worked perfect, I had no idea I needed to do that, or that it was specific to a certain data type! – Rick Hammer Mar 27 '16 at 18:43
Now you know @RickHammer! ;) – gsamaras Mar 27 '16 at 18:45

score 0 · Answer 2 · answered Mar 27 '16 at 18:30

0

%d is not a correct conversion for float, use %f instead

change:

printf("Floats (a,b) and quotient (c) are : %d,%d,%d \n", a,b,c);

to:

printf("Floats (a,b) and quotient (c) are : %f,%f,%f \n", a,b,c);

and you should be fine.

answered Mar 27 '16 at 18:30

Charlestone

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Having issues with C using float and printf

2 Answers2