android json starting with string

Question

returnLogin([{
    "id": 0,
    "first_name": "abc",
    "last_name": "xyz",
    "msg": "Invalid User or Location ID or Password.",
    "location_id": "",
}])

How to get data from above Json string? here json start with witn string not any bracket thats why i try to. getting data

try { JSONObject jsonObject=new JSONObject(response); System.out.println("jsonResponse" + jsonObject); } catch (JSONException e) { e.printStackTrace(); } — Manish, Mar 28 '16 at 05:44

score 0 · Answer 1 · answered Mar 28 '16 at 05:20

0

you can parse like below,

String data = "";// here your json data which will parse
        try {
            JSONArray jsonArray = new JSONArray(data);
            JSONObject jsonObject=jsonArray.getJSONObject(0);
            int id=jsonObject.getInt("id");
            String first_name=jsonObject.getString("first_name");
            String last_name=jsonObject.getString("last_name");
            String msg=jsonObject.getString("msg");
            String location_id=jsonObject.getString("location_id");
        } catch (JSONException e) {
            e.printStackTrace();
        }

But before parse correct your data.

answered Mar 28 '16 at 05:20

Dhaval Solanki

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its going in to JSONexception :: org.json.JSONException: Value returnLogin( of type java.lang.String cannot be converted to JSONArray – Manish Mar 28 '16 at 05:42
Because your data was wrong please correct it, – Dhaval Solanki Mar 28 '16 at 05:43
please put your original json data, – Dhaval Solanki Mar 28 '16 at 05:44
its my all the response:: returnLogin([{"id":0,"first_name":"","last_name":"","msg":"Invalid User or Location ID or Password.","location_id":"","reg_id":"","emp_id":"","emp_pass":"","currency_symbol":"","access_timeattendance":"","location_register_services":"","location_manager_req_discount":"","location_manager_req_adjustment":"","access_retail_fast_posting":"","access_retail_fast_posting_new_check":"","check_style":"","print_technician_copy":""}]) – Manish Mar 28 '16 at 05:48
how to removew "returnLogin(" from my json... i thing this remove after solve that insssue – Manish Mar 28 '16 at 05:50
yes you require to remove it, – Dhaval Solanki Mar 28 '16 at 05:52
for remove yourresponse.replace("returnLogin(".""); – Dhaval Solanki Mar 28 '16 at 05:53
and also next time yourresponse.replace(")".""); – Dhaval Solanki Mar 28 '16 at 05:54

android json starting with string

1 Answers1