Searching lists then calling same place from other lists

Question

I wish for my program to search resident and if it a specific value it will print the same placed data from other lists. For example in this situation I would want it to print;

"Name is Alan, age is 7 and they do not live in place",

as well as,

"Name is Margaret, age is 66 and they do not live in place"

name = ["Alan", "Susan", "Margaret"]
age = [7, 34, 66]
resident = [0, 1, 0]

if resident = 0:
    print ("name is {}, age is {} and they do not live in place".format(name[], age[]))

Answer 1

for person, ages, residency in zip(name,age,resident):
    if residency == 0:
        print("name is {0}, age is {1} and they do not live in place".format(person, ages))

zip takes multiple lists and returns a list of tuples. Here's an example:

zip(name, age, resident)
>>>> [('Alan', 7, 0), ('Susan', 34, 1), ('Margaret', 66, 0)]

Iterating over each tuple is then very easy.

Answer 2

Consider also the use of enumerate, which will provide the index and item from the iterated list:

>>> for i,x in enumerate(resident):
        if x == 0:
            print("name is {0}, age is {1} and they do not live in place".format(name[i], age[i]))


name is Alan, age is 7 and they do not live in place
name is Margaret, age is 66 and they do not live in place

Answer 3

You can use the commonly used %s string replacement:

name = ["Alan", "Susan", "Margaret"]
age = [7, 34, 66]
resident = [0, 1, 0]

if resident[0] == 0:print ("name is %s, age is %s and they do not live in place"%(name[0],age[0]))