PHP If statement responding with all code rather than printing answer

Question

I'm fairly new to programming. I'm trying to write what should be a fairly basic if, elseif piece of code for my database, but when it compiles it just prints the code from the first if statement all the way to the end. I've been going over it for days and can't work out where I'm going wrong

<!DOCTYPE html>
<html>
<body>

<?php
$row = "A1 Header";
$compulsary = FALSE;
$mutable = TRUE;
$included = FALSE;

if ($compulsary == FALSE and $mutable == TRUE) {
        echo "<textarea style=background-color:yellow; name=\"message\">Please Enter</textarea><br>";
    }
elseif ($compulsary == FALSE and $mutable == FALSE){    
        echo "'"$row"'";
        }

elseif ($compulsary == True and $mutable == True) {
    echo "<textarea style=background-color:yellow; name=\"message\">Please Enter</textarea><br>";
    }
else {
    echo "'"$row"'";
    }
?>

</body>
</html>

If you can see your PHP code... Your server isn't configured to process it properly. How are you calling this file? What is its name? — andrewsi, Apr 04 '16 at 13:10
Also, in your code on lines 15 and 22 your not concatenating the strings before echoing them, you should so it should be: `echo "'" . $row . "'";` — C.Liddell, Apr 04 '16 at 13:13

score 0 · Answer 1 · answered Apr 04 '16 at 13:13

try this

<!DOCTYPE html>
<html>
    <body>

        <?php
        $row = "A1 Header";
        $compulsary = FALSE;
        $mutable = TRUE;
        $included = FALSE;

        if ($compulsary == FALSE and $mutable == TRUE) {
            echo "<textarea style=background-color:yellow; name=\"message\">Please Enter</textarea><br>";
        } elseif ($compulsary == FALSE and $mutable == FALSE) {
            echo "'".$row."'";
        } elseif ($compulsary == True and $mutable == True) {
            echo "<textarea style=background-color:yellow; name=\"message\">Please Enter</textarea><br>";
        } else {
            echo "'".$row."'";
        }
        ?>

    </body>
</html>

Still the same issue, prints out everything from the first Please Enter to the end, with only the second Please Enter being in a text box. — Dwhite, Apr 05 '16 at 11:43

score 0 · Accepted Answer · answered Apr 04 '16 at 13:20

You can do like this:  



<!DOCTYPE html>
    <html>
    <body>

    <?php
    $row = "A1 Header";
    $compulsary = FALSE;
    $mutable = TRUE;
    $included = FALSE;

    if ($compulsary == FALSE and $mutable == TRUE) {
            echo "<textarea style='background-color:yellow;' name='\"message\"'>Please Enter</textarea><br>";
        }
    elseif ($compulsary == FALSE and $mutable == FALSE){    
            echo $row;
            }

    elseif ($compulsary == TRUE and $mutable == TRUE) {
        echo "<textarea style='background-color:yellow;' name='\"message\"'>Please Enter</textarea><br>";
        }
    else {
        echo $row;
        }
    ?>

    </body>
    </html>

I put the same code through my laptop and it was fine, thanks :) — Dwhite, Apr 07 '16 at 07:48

score -2 · Answer 3 · edited Apr 04 '16 at 15:44

-2

I think you have a syntax error. Try this:

echo "'\"$row\"'";

edited Apr 04 '16 at 15:44

Andrei

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answered Apr 04 '16 at 13:16

cakecoke

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PHP If statement responding with all code rather than printing answer

3 Answers3