Python one liner to ensure 0 <= value <= 1?

Question

I was wondering if there's a way of compacting this code:

foo = calculate() # 'calculate' is some kind of function which
                  # could return float values less than 0.0 or more than 1.0
                  # It's here only as a (hopefully) clarification
bar = foo * 5 
if bar < 0:
    bar = 0
elif bar > 1:
    bar = 1
else:
    pass # 'bar' has a good value within the "range"

I know I could do bar = max(foo * 5, 0) or bar = min(foo * 5, 1) but... Is there a way of doing this in only one line? Something like bar = ensure_between(0, foo * 5, 1) or something like that?

It's not a big deal, I'm just curious.

Thank you in advance :-)

http://stackoverflow.com/questions/4092528/how-to-clamp-an-integer-to-some-range-in-python — zch, Apr 04 '16 at 14:22
@TigranSaluev Yes, absolutely! Good catch. Bad translation from the actual code into foobars :D Sorry (edited the question as it should've been done) — Savir, Apr 04 '16 at 14:35

score 3 · Accepted Answer · edited May 23 '17 at 12:16

3

A one-liner using min and max, resulting in either a number between 0 and 1, is this what you're looking for?

foo = max(0, min(foo, 1))

More suited to the example is

bar = max(0, min(foo, 1))

EDIT: fixed by removing the lists as soon pointed out

edited May 23 '17 at 12:16

Community

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answered Apr 04 '16 at 14:34

Jamtot

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1
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No reason for inner list, just `max(0, min(foo, 1))` – awesoon Apr 04 '16 at 14:35

Python one liner to ensure 0 <= value <= 1?

1 Answers1