How to obtain the end of the day when given a LocalDate?

Question

I could get it by doing

LocalDateTime.of(LocalDate.now(), LocalTime.of(23, 59, 59));

But is there an equivalent 'atStartOfDay' method for the end of the day?

LocalDate.now().atStartOfDay();
LocalDate.now().atEndOfDay(); //doesn't work

What do you mean by "end of the day"? The start of the following day minus 1 second? 1 millisecond? 1 nanosecond? Why not just use the beginning of the next day, and use `[day, day + 1[` intervals? When a shop is open from 8AM to 6PM, the end time displayed is 6PM, not 5:59:59 PM. — JB Nizet, Apr 04 '16 at 17:01
This answer also contains a solution for a ZonedDateTime https://stackoverflow.com/a/50400321/1658268 — SudoPlz, May 17 '18 at 20:53

score 171 · Accepted Answer · answered Apr 04 '16 at 17:07

171

Here are a few alternatives, depending on what you need:

LocalDate.now().atTime(23, 59, 59);     //23:59:59
LocalDate.now().atTime(LocalTime.MAX);  //23:59:59.999999999

But there is no built-in method.

As commented by @JBNizet, if you want to create an interval, you can also use an interval up to midnight, exclusive.

answered Apr 04 '16 at 17:07

assylias

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What about daylight saving time? – Mateus Viccari Mar 17 '17 at 12:28
2

@MateusViccari LocalDate / LocalDateTime have no time zone so no DST rule. Not sure what you are asking about. – assylias Mar 17 '17 at 13:09

score 52 · Answer 2 · edited Sep 18 '22 at 19:12

These are the variants available in LocalTime, notice MIDNIGHT and MIN are equal.

LocalDate.now().atTime(LocalTime.MIDNIGHT); //00:00:00.000000000
LocalDate.now().atTime(LocalTime.MIN);      //00:00:00.000000000
LocalDate.now().atTime(LocalTime.NOON);     //12:00:00.000000000
LocalDate.now().atTime(LocalTime.MAX);      //23:59:59.999999999

For reference, this is the implementation in java.time.LocalTime

/**
 * Constants for the local time of each hour.
 */
private static final LocalTime[] HOURS = new LocalTime[24];
static {
    for (int i = 0; i < HOURS.length; i++) {
        HOURS[i] = new LocalTime(i, 0, 0, 0);
    }
    MIDNIGHT = HOURS[0];
    NOON = HOURS[12];
    MIN = HOURS[0];
    MAX = new LocalTime(23, 59, 59, 999_999_999);
}

If the value assigned to the 4th constructor argument (999_999_999) of LocalTime (representing nanoOfSecond) looks unfamiliar it's because it's making use of the Java 7 feature Underscores in Numeric Literals.

In Java SE 7 and later, any number of underscore characters (_) can appear anywhere between digits in a numerical literal. This feature enables you, for example, to separate groups of digits in numeric literals, which can improve the readability of your code.

score 9 · Answer 3 · answered Apr 04 '16 at 17:01

9

Get start of next day and subtract 1 second from it. This should work for you. :

public static void main(String[] args) {

    LocalDate date = LocalDate.now();
    LocalDateTime dt = date.atStartOfDay().plusDays(1).minusSeconds(1);
    System.out.println(dt);
}

O/P :

2016-04-04T23:59:59

answered Apr 04 '16 at 17:01

TheLostMind

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note this is 1 second, not one millisecond, I would advise against this hack – Bojan Petkovic Jan 28 '19 at 16:16
this is brilliant !! – Basil Battikhi Jul 26 '21 at 20:03
2

This will get you only the time at 23:59:59.000000000. So if you use this solution you should be aware of that. It's safer to use the accepted answer: https://stackoverflow.com/a/36408726/2294031 – domids Jul 28 '21 at 11:06

score 2 · Answer 4 · answered Aug 17 '20 at 10:37

public static long getStartOfDay(String country) {
    return LocalDate.now().atStartOfDay(ZoneId.of("Europe/Berlin")).toInstant().toEpochMilli();
}

public static long getEndOfDay(long startOfDay) {
    return startOfDay + 86399000L;  // adding 24h = 1day seconds - 1
}

public static long getStartOfDay(LocalDate localDate, String country) {
    return localDate.atStartOfDay(ZoneId.of("Europe/Berlin")).toInstant().toEpochMilli();
}

public static long getEndOfDay(LocalDate localDate, String country) {
    localDate = localDate.plusDays(1L);
    return localDate.atStartOfDay(ZoneId.of("Europe/Berlin")).toInstant().toEpochMilli() - 1000L; //substract mili
}

How to obtain the end of the day when given a LocalDate?

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