I want to take image as input into my web page. I have written following code in my jsp for this :-
<form action="Upload" method="get" enctype="multipart/form-data">
Image<input type="file" name="image" accept="image/jpg" id="image">
<input type="submit" value="submit">
</form>
but I do not know how to receive the "image" parameter in a servlet that is whether it should be a input stream or file, I have no idea. Please tell me the correct code for it.
Use Apache Commons File. The form method must be method="POST". Then in your web.xml you need to map the request to your servlet:
<servlet>
<servlet-name>MyServlet</servlet-name>
<servlet-class>com.stackoverflow.MyServletClass</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>MyServlet</servlet-name>
<url-pattern>/Upload</url-pattern>
</servlet-mapping>
Then you write a class that extends HttpServlet and implement to doPost() method.
well, just go here: http://www.codejava.net/java-ee/servlet/apache-commons-fileupload-example-with-servlet-and-jsp
After painstaking efforts and google search I found a solution to my problem. A page from Stackoverflow helped very much. First I changed the get method of my form to post like this
<form action="Upload" method="post" enctype="multipart/form-data">
Image<input type="file" name="image" id="image" accept="image/jpg">
<input type="submit" value="submit">
</form>
Then I wrote the following servlet code. We accept the <input type="file">data as Part data in servlet. Then we convert it to input stream. The input stream then can be saved in database. Here is my Servlet:-
package controller;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.nio.file.Path;
import java.nio.file.Paths;
import java.sql.Connection;
import java.sql.PreparedStatement;
import java.sql.SQLException;
import javax.servlet.ServletException;
import javax.servlet.annotation.MultipartConfig;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.http.Part;
import model.ConnectionManager;
@MultipartConfig(location="/tmp", fileSizeThreshold=1048576, maxFileSize=20848820, maxRequestSize=418018841)
public class Upload extends HttpServlet {
@Override
protected void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
Part filePart=request.getPart("image");`// Retrieves <input type="file" name="image">`
String filePath = filePart.getSubmittedFileName();//Retrieves complete file name with path and directories
Path p = Paths.get(filePath); //creates a Path object
String fileName = p.getFileName().toString();//Retrieves file name from Path object
InputStream fileContent = filePart.getInputStream();//converts Part data to input stream
Connection conn=ConnectionManager.getConnection();
int len=(int) filePart.getSize();
String query = ("insert into IMAGETABLE(ID,NAME,LENGTH,IMAGE) VALUES(?,?,?,?)");
try {
PreparedStatement pstmt = conn.prepareStatement(query);
pstmt.setInt(1, 5);
pstmt.setString(2, fileName);
pstmt.setInt(3, len);
pstmt.setBinaryStream(4, fileContent, len);
success=pstmt.executeUpdate();
} catch (SQLException ex) {
System.out.println("Error : "+ex.getMessage());
}finally{
try{
if(fileContent!=null)fileContent.close();
if(conn!=null)conn.close();
}catch(IOException | SQLException ex){
System.out.println("Error : "+ex.getMessage());
}
}
}
}
After execution, it does the job successfully. We accept the image from user and save it in database. Hope this solution will help all :)
For upload file in folder we need first create html file and Second jsp , In HTML write code like:
<input type="file" name="image" class="form-control" required>
In JSP write code kike:
MultipartRequest m = new MultipartRequest(request, "PathOfFile")
Note: You must add the following jar files
