PHP catching undefined variable error

Question

How do I go about catching an undefined variable error in PHP? I have a variable called $place that will only have a value if the user enters some details on another page, however if it has no value then it has an undefined variable error on the screen which I don't want. I tried:

<?php try{ echo $place; }catch(Exception $e){echo 'No Place Set';}?>

but that doesn't work. Any suggestions?

The question is fine, no editing needed because is clearly not a duplicate. This header talks about the usage of try-catch or "catching" using exception handling. However the referred one has not even a single mention to this structure. The question is fine, no editing needed — Mbotet, Jan 14 '21 at 13:02

score 2 · Accepted Answer · edited Apr 05 '16 at 17:07

2

undefined variables can be corrected by DEFINING them.

for instance:

$place = ''; OR $place = null;

defines the variable. you will not get any error or warning.

Or use if(isset($place)){}

edited Apr 05 '16 at 17:07

urfusion

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answered Apr 05 '16 at 13:10

Daniel PurPur

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score 0 · Answer 2 · edited Apr 05 '16 at 14:04

0

just use isset() to determine if the variable is set.

if(isset($place)){
    echo $place;
}else{
    echo 'No Place Set';
}

edited Apr 05 '16 at 14:04

Natalie Hedström

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answered Apr 05 '16 at 13:10

urfusion

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score 0 · Answer 3 · answered Apr 05 '16 at 13:10

0

Why are you using try-catch for that? Just use isset

<?php 

if(isset($place)){
    echo $place;
} else {
    echo 'No Place Set';
}

answered Apr 05 '16 at 13:10

Harikrishnan

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PHP catching undefined variable error

3 Answers3