Can't count the number above 3 billion

Question

I've got a problem here, when I calculate a figure of more than 2 billion and 3 billion are always error and displays the force close. So what I need to fix it

long  initial_investment, total_investment;
 DecimalFormat df = new DecimalFormat ("###,###,###,###");
initial_investment = Integer.parseInt( Text1.getText().toString());


if (initial_investment <= 1000000000)
                 {

                     total_investment = ((initial_investment * 3) /100)+ total_investment;
                     Text5.setText(df.format(total_investment));

                 }
                 else if (initial_investment > 1000000000 && initial_investment <= 3000000000L )
                 {

                     total_investment = (long) (((initial_investment* 2.5) /100)+ total_investment);
                     Text5.setText(df.format(total_investment));

                 }
                 else if (initial_investment > 3000000000L )
                        {

                        total_investment = ((initial_investment * 2) /100)+ total_investment;
                        Text5.setText(df.format(total_investment));

                        }

            }

http://stackoverflow.com/questions/15004944/max-value-of-integer — CommonsWare, Apr 05 '16 at 23:55
Is `initial_investment` an integer? Integers can't go above 2.14 billion. — Matthew Wright, Apr 05 '16 at 23:55
the example doesn't show whether the initial_investment is an integer or long... — ssk, Apr 05 '16 at 23:56

score 2 · Answer 1 · answered Apr 05 '16 at 23:59

2

I would suggest you to use BigInteger if you are dealing with some very large value. You can use it as shown below

BigInteger bi1, bi2, bi3;  

// assign values to bi1, bi2
bi1 = new BigInteger("123");
bi2 = new BigInteger("50");

// perform add operation on bi1 using bi2
bi3 = bi1.add(bi2);

String str = "Result of addition is " +bi3;

answered Apr 05 '16 at 23:59

S4beR

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what is the meaning of the quotation marks "123" and "50" ? – Ricky AN Apr 06 '16 at 00:35
@RickyAN BigInteger takes the number in as a string – intboolstring Apr 06 '16 at 01:16
@intboolstring The method parseInt(String) is undifined for the type BigInteger – Ricky AN Apr 06 '16 at 01:40
why do you need a `parseInt` type of method when constructor itself can convert `String` to `BigInteger`? – S4beR Apr 06 '16 at 06:57

score 0 · Answer 2 · answered Apr 06 '16 at 01:43

0

You could do something like

initial_investment= Long.parseLong( Text1.getText().toString());

instead of

initial_investment = Integer.parseInt( Text1.getText().toString());

answered Apr 06 '16 at 01:43

Yair Kukielka

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If this helped you, you could accept it as the correct answer ;) – Yair Kukielka Apr 06 '16 at 02:00

score 0 · Answer 3 · answered Apr 06 '16 at 01:55

0

Sorry this is my fault, but now I've had to fix it I just need to change initial_investment from int to an long

initial_investment = Long.parseLong( Text1.getText().toString());

answered Apr 06 '16 at 01:55

Ricky AN

1
3

Can't count the number above 3 billion

3 Answers3