How to include an if-statement inside a PHP echo?

Question

 for ($i=0; $i<$total_questions_for_exam; $i++) {

        $question_id= $question_and_answers[$i]['question_id'];
        $numberofanswersperquestion = count_answers_belongToOne_questionNew($question_id);
        //die(var_dump($question_id)); 
        $student_answer_per_question = retrieve_student_result ($_SESSION['user_id'], $_GET['quiz_id'], $question_id);
         echo '   <table class="table table-bordered table-condensed table-datatable table-hover">
                    <tbody>

                        <tr>
                            <td style="text-align: left;" width="100%"><strong>Question '. ($i+1) .'</strong></td> 
                        </tr>
                        <tr>
                            <td style="text-align: left;" width="100%">' . $question_and_answers[$i]['question_name'] .'</td>
                        </tr>



                        <tr>
                            <td style="text-align: left;" width="100%" class="warning"><em>Question Not attempted</em><br><strong>Correct Answer is</strong><br>' . $numberofanswersperquestion[0]['answer_name'] . '</td>
                        </tr>

                        <tr>
                            <td style="height: 5px;" width="100%">&nbsp;</td>
                        </tr>

                        <tr>
                        <td style="height: 5px;" width="100%">&nbsp;</td>
                        </tr>

                    </tbody>
                    </table>';

 }

Hi guys I have this for loop, what I am trying to do is, only print this

<tr>
    <td style="text-align: left;" width="100%" class="warning"><em>Question Not attempted</em><br><strong>Correct Answer is</strong><br>' . $numberofanswersperquestion[0]['answer_name'] . '</td>
</tr>

based on an if statement. But how can put that if statement inside that echo ??

I have tried this way, by

' . if() {} . '

but I couldn't get it to work this way.

this is what I want inside the if statement

if($student_answer_per_question === '' || '') {
 <tr>
    <td style="text-align: left;" width="100%" class="warning"><em>Question Not attempted</em><br><strong>Correct Answer is</strong><br>' . $numberofanswersperquestion[0]['answer_name'] . '</td>
</tr>
}

I hope I have explained the problem in detail and I appreciate any help from you guys. Thanks

`if($student_answer_per_question === '' || '') {` `''` [will always be falsy](https://3v4l.org/dPjXK) — PeeHaa, Apr 06 '16 at 10:45
So this is how it looks currently, https://gyazo.com/cad66adb763d2ffc23b71b5a9c500231 — dark_illusion_909099, Apr 06 '16 at 11:07
if statement is working fine now but that else statement is not getting called for some reason — dark_illusion_909099, Apr 06 '16 at 11:07

score 1 · Accepted Answer · answered Apr 06 '16 at 10:56

You can temporarily define a variable to store your output.

$output = '<table class="table table-bordered table-condensed table-datatable table-hover">
                <tbody>

                    <tr>
                        <td style="text-align: left;" width="100%"><strong>Question '. ($i+1) .'</strong></td> 
                    </tr>
                    <tr>
                        <td style="text-align: left;" width="100%">' . $question_and_answers[$i]['question_name'] .'</td>
                    </tr>';
if(condition)
{
$output .= '             <tr>
                        <td style="text-align: left;" width="100%" class="warning"><em>Question Not attempted</em><br><strong>Correct Answer is</strong><br>' . $numberofanswersperquestion[0]['answer_name'] . '</td>
                    </tr>';
}
$output .=              '<tr>
                        <td style="height: 5px;" width="100%">&nbsp;</td>
                    </tr>

                    <tr>
                    <td style="height: 5px;" width="100%">&nbsp;</td>
                    </tr>

                </tbody>
                </table>';

after making some change, this is currently how it is, https://gyazo.com/cad66adb763d2ffc23b71b5a9c500231 — dark_illusion_909099, Apr 06 '16 at 11:05
would you have any idea, why that else not getting called ?? that if statement is working now, but that else echo is not getting called at all — dark_illusion_909099, Apr 06 '16 at 11:06
Thanks I fixed it, it was that if statement, should have been like this if($student_answer_per_question == '') — dark_illusion_909099, Apr 06 '16 at 11:14

score -1 · Answer 2 · answered Apr 06 '16 at 10:56

Create a variable, before the echo statement for example $statement and use PHP Shorthand If/Else, something like this

$statement = ($student_answer_per_question == '')? "Option 1" : "Option 2";

Now you can just print the $statement within your echo statement, as

echo "blah blah $statement blah blah";

How to include an if-statement inside a PHP echo?

2 Answers2