How to parse this JSON on android volley

Question

Here is the output that I need to parse. The values of usertype_name should be stored into a String array. Please help me out.

{
    0: {
    usertype_name: "Member-Individual"
    },
    1: {
    usertype_name: "Member-Institutional"
    },
    2: {
    usertype_name: "Officer-Member"
    },
    3: {
    usertype_name: "Officer-Admin"
    },
    4: {
    usertype_name: "Officer-President"
    },
    current_position: "Member-Individual"
}

When parsing JSON on volley, normally I just do it like this:

public void onResponse(String s) {
    JSONArray array= new JSONArray(s.toString());
    for(int i = 0; i < array.length(); i++) {
        JSONObject object = array.getJSONObject(i);
        String text = object.getString("usertype_name");
    }
}

But since there are incremental numbers showing on the result, which are weird for me, makes it confusing. Let me also post my webservice code. It goes like this, the usertype_name are results of a query and the current_position is a result of another query. If I'll remove the current_position, the numbers will disappear.

$result = mysql_result(mysql_query($query),0);
$result2 = mysql_query($query2);

while($line = mysql_fetch_array($result2, MYSQL_ASSOC)){
    $results[] = $line;
    }
$results['current_position'] = $result;

echo (json_encode($results));

Yeah... You are going to have to add more data. Where is your code? Are you using Volley already? Show it. — CaptJak, Apr 06 '16 at 18:16
Actually... That isn't valid JSON. Integers and plain-text can't be keys. — OneCricketeer, Apr 06 '16 at 18:19
How would I make it a valid JSON while keeping the `current_position` value? — Glen, Apr 06 '16 at 18:36
Read the documentation on [`json_encode`](http://php.net/manual/en/function.json-encode.php). It looks like you need an associative array. I'm not sure what the mysql result is giving you. — OneCricketeer, Apr 06 '16 at 20:45

Krish · Answer 1 · 2016-04-06T20:40:29.990

0

Change your json string like this ,

{
  "array": [
    "Member-Individual",
    "Member-Institutional",
    "Officer-Member"
  ],
  "current_position": "6"
}

And the php code example :

 <?php
    class User {
        public $array = array("Member-Individual", "Member-Institutional", "Officer-Member");
        public $current_position = "6";

        public function __construct() {

        }
    }



    $user = new User();

    echo json_encode($user);
?>

edited Apr 06 '16 at 20:40

answered Apr 06 '16 at 20:07

Krish

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can you help me on how to do that on php? I'm not familiar on that :( – Glen Apr 06 '16 at 20:27
Refer http://nitschinger.at/Handling-JSON-like-a-boss-in-PHP/ – Krish Apr 06 '16 at 20:31
I have edited the answer . please have a look. – Krish Apr 06 '16 at 23:23

How to parse this JSON on android volley

1 Answers1