python - not sure how to build following regex

Question

I want to replace

'this is my string (anything within brackets)'

with

'this is my string '

a concrete sample would be:

'Blue Wire Connectors (35-Pack)'

should be replaced with

'Blue Wire Connectors '

can anyone suggest how to build this regex in python?

score 1 · Accepted Answer · 2016-04-10T01:38:38.480

1

Simply search with (\([^)]*\)) and replace with empty string "".

This regex is capturing everything within ( ) until a ) is reached i.e end of parenthesis.

Regex101 Demo

edited Apr 10 '16 at 01:38

answered Apr 10 '16 at 01:27

the capture group is useless. – Casimir et Hippolyte Apr 10 '16 at 01:42
@CasimiretHippolyte: Incase OP wishes to replace matched pattern with something else. And my bad habit. – Apr 10 '16 at 01:44
even in this case it's useless. – Casimir et Hippolyte Apr 10 '16 at 01:46
@CasimiretHippolyte: Could be useful when appending with matched pattern. Like `something\1` or `\1something`. – Apr 10 '16 at 01:50
It isn't the question here. – Casimir et Hippolyte Apr 10 '16 at 02:35
@CasimiretHippolyte: Okay. – Apr 10 '16 at 02:35

user2390182 · Answer 2 · 2016-04-10T01:47:34.363

The pattern to be replaced should look about like that: r'\(.*?\)' which matches bracketed expressions non-greedily in order to avoid matching multiple bracketed expressions as one (Python docs):

import re

s = 'this (more brackets) is my string (anything within brackets)'
x = re.sub(r'\(.*?\)', '', s)
# x: 'this  is my string '

Note, however, that nested brackets 'this (is (nested))' are a canonical example that cannot be properly handled by regular expressions.

python - not sure how to build following regex

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