How to store a big floating point number in python variable?

Question

In python why result become zero when i multiply anyother value with 5.55375797812e+28 .
But we all Know Python accept a very big range value.

[`decimal.Decimal`](https://docs.python.org/2/library/decimal.html#decimal-objects), your question is however off topic for stackoverflow as you are asking to find some tool for you. — Tadhg McDonald-Jensen, Apr 10 '16 at 16:08

score 3 · Accepted Answer · answered Apr 10 '16 at 16:09

You can use the built-in decimal library.

import decimal

decimal.getcontext().prec = 46 # Change 46 to the precision you want.
result = decimal.Decimal(1.6) / decimal.Decimal(7)

print(result)
Decimal('0.2285714285714285841168345671446461762700762068')

Keep in mind that when you have to use the set precision you always need to enclose the number in decimal.Decimal() and you will always get Decimal() returned.

How to store a big floating point number in python variable?

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