0

I Have following two classes: Test.java

package com.test.app;

public class Test {

    public int a=10;
    protected void testFunc() {
        // TODO Auto-generated method stub
        System.out.println("Test class--> testFunc");
    }
}

Another One is Main.java package com.test.main;

import com.test.app.Test;


public class Main extends Test {


    public static void main(String[] argv) {

        System.out.println("Main Method");

        Main main =new Main();
        main.testFunc(); // No Error


        Test test = new Test();
        test.testFunc(); // Error

    }

}

The method test.testFunc() from the type Test is not visible

1 Answers1

1

The Test#testFunc() method is only accessible for sub-classes (like Main) and for classes in the same package (com.test.app).

This is why the statement 

main.testFunc();

compiles fine (because Main is a sub-class of Test and it's allowed to call testFunc()).

This statement, however

test.testFunc();

doesn't compile, because the package where the Main class is located is not com.test.app, but com.test.main.

More info:

Community
  • 1
  • 1
Konstantin Yovkov
  • 62,134
  • 8
  • 100
  • 147
  • [this, especially the top comment on the accepted answer](http://stackoverflow.com/a/215505/2988942) is a nice reference/proof addition to your answer :) – Phantomazi Apr 12 '16 at 09:27
  • Yes I agree with your answer but here my question is I'm extending from super class so in this case protected methods should be available in different package ?? –  Apr 12 '16 at 10:43
  • So in above Main class can get feature of Test class including protected method right!?? But testFunc() can not visible in Main class when I used object of Test class I.e test.testFunc() –  Apr 12 '16 at 16:34