PHP Notice: Undefined index:

Question

function drupal_build_css_cache($css) {
  $data = '';
  $uri = '';
  $map = variable_get('drupal_css_cache_files', array());
  // Create a new array so that only the file names are used to create the hash.
  // This prevents new aggregates from being created unnecessarily.
  $css_data = array();
  foreach ($css as $css_file) {
    $css_data[] = $css_file['data'];
  }

PHP Notice: Undefined index: data on line 3606. Line 3606 being: $css_data[] = $css_file['data'];

Notice: Undefined index can be ignored , and if you don't want to ignore split $css_file in foreach($css as $css_file_var => $css_file_value). — Nirpendra Patel, Apr 13 '16 at 11:39
First, I would like to know what is problem and what do you expet? Second, please read this [Notice undefined index](http://stackoverflow.com/questions/12769982/reference-what-does-this-error-mean-in-php/12770836#12770836) if you want to get rid of the error. — , Apr 13 '16 at 11:56
You might want to print_r $css_file to see the indexes that are available within the array — Markus Müller, Apr 13 '16 at 12:42
@NirpendraPatel you should not just ignore notices. They may not crash your code directly, but most likely lead to some errors. In this case `$css_file['data']` seems to not exist, so you should check for the key and react to the result. — enricog, Apr 13 '16 at 12:42
No, you must not ignore it. It's an indication that your input is not as expected, which means you may need additional validation of that input, or at least a check like `if (isset($css_file['data'])) $css_data[] = $css_file['data'];` — Michael Berkowski, Apr 13 '16 at 12:42

score 3 · Answer 1 · answered Apr 13 '16 at 12:42

3

To avoid this error just test if the table fields was initialized with isset () .

// Before using $css_file['data'];
if (isset($css_file['data']))
{
    $css_data[] = $css_file['data'];   
}

answered Apr 13 '16 at 12:42

DevLoots

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Thanks..its fixed now. – Iron Butterfly Apr 19 '16 at 06:05

score 1 · Answer 2 · answered Apr 13 '16 at 12:52

It is just notice, that you have undefined index; you should first check if is it set:

if (isset($css_file['data'])) {
  $css_data[] = $css_file['data'];   
}

Otherwise you can turn off notice reporting (put this line at the beginning of your code):

error_reporting(E_ALL ^ E_NOTICE);

score 0 · Answer 3 · answered Apr 13 '16 at 12:41

0

PHP notice is telling you that $css_file has no key data. Check what you receive in $css variable.

answered Apr 13 '16 at 12:41

Justinas

41,402
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score 0 · Answer 4 · answered Apr 13 '16 at 12:43

0

First, you should show what you've tried to fix the issue. As the error shows, it's caused because $css_file['data'] is undefined. You haven't shown us where $css_file is defined. $css_file['data'] is most likely not being defined.

answered Apr 13 '16 at 12:43

Goose

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PHP Notice: Undefined index:

4 Answers4