How to safely wrap optional values in Swift?

Asked Apr 13 '16 at 12:33

Active Apr 13 '16 at 12:33

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I have got this piece of code :

     var array: [Int]? = []

 array = data.characters.split(){$0 == ","}.map{
        (Int(String.init($0).
stringByTrimmingCharactersInSet(NSCharacterSet.whitespaceCharacterSet())))!}

which reads the data from the file and if there are Ints separated by a single comma, it will convert them into array of Int. My question is how do I safely wrap it so I dont get this error : fatal error: unexpectedly found nil while unwrapping an Optional value ?

asked Apr 13 '16 at 12:33

user3395936

Remove the `!` and use `flatMap` instead of `map`. – Eric Aya Apr 13 '16 at 12:43
@EricD thank you Eric, that worked! – user3395936 Apr 13 '16 at 13:09

How to safely wrap optional values in Swift?

0 Answers0