Python dictionary: print sorted values per key string

Question

I have a Python dictionary which holds pairs of key/value:

visited = {
'3':['A', '0'], 
'25':['U', '3'],
'1':['G', '0'],
'32':['C', '0'],
'24':['C', '1'],   
'27':['U', '0'],
'17':['C', '5'], 
'15':['G', '1'], 
'4':['G', '2']
}

I tried to sort them with collections

import collections

...

s = collections.OrderedDict(sorted(visited.items()))
for k, v in s.iteritems():
    print ' '.join(v)

And I receive:

How could I repare it:

See [Does Python have a built in function for string natural sort?](http://stackoverflow.com/q/4836710) — Bhargav Rao, Apr 13 '16 at 18:50
For the record, no, natsort is not a good idea - it is an overkill. See wim's answer. — Antti Haapala -- Слава Україні, Dec 05 '16 at 21:04

score 4 · Accepted Answer · answered Apr 13 '16 at 18:53

You are sorting strings and you wanted to sort by numbers:

>>> s = OrderedDict((k, visited[k]) for k in sorted(visited, key=int))
>>> s
OrderedDict([('1', ['G', '0']),
             ('3', ['A', '0']),
             ('4', ['G', '2']),
             ('15', ['G', '1']),
             ('17', ['C', '5']),
             ('24', ['C', '1']),
             ('25', ['U', '3']),
             ('27', ['U', '0']),
             ('32', ['C', '0'])])

Python dictionary: print sorted values per key string

1 Answers1