2016-04-16" in PHP

Asked Apr 14 '16 at 07:21

Active Apr 14 '16 at 07:41

Viewed 31 times

I try to get $price, but something wrong. I think that 2016-04-16 can't be read. But I don't know how to fix it.

Here is result:

Array
(
    [success] => 1
    [data] => Array
        (
            [2016-04-16] => Array
                (
                    [name] => Nickola
                    [tag] => old
                    [price] => 206
                )

        )

)

Here is php:

<?php
    $wall = file_get_contents("XXX"); //request info
    $wall = json_decode ($wall, true); // convert JSON-string to array
    echo '<pre>'; print_r($wall); echo '</pre>'; //print array to check it OK.
    $wall = $wall->data->2016-04-16; // getting array with value I need
    for ($i = 0; $i < count($wall); $i++) {
    echo $wall[$i]->price; // print
    }
    ?>

edited Apr 14 '16 at 07:41

halfer

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asked Apr 14 '16 at 07:21

Nes

Should be `$arr['index']` not `->` – aldrin27 Apr 14 '16 at 07:23
An `array` is not an `object`. – arkascha Apr 14 '16 at 07:23
You passed in true as second parameter to json_decode thats why you need to access it using ['key'] instead of -> notation. – Mubashar Abbas Apr 14 '16 at 07:24
Thanks for reply. I tried this, but no result :( `echo $wall[data][2016-04-16][name]; ` – Nes Apr 14 '16 at 08:40
`$price = $wall["data"]["2016-04-16"]["price"];` works! Thank your for your help! – Nes Apr 14 '16 at 11:57

Can't get value from array "$wall = $wall->data->2016-04-16" in PHP

0 Answers0