How to stop a function that runs every 7 seconds if it finds any data?

Question

The following runs every 7 second and calls the showAlert() function. It looks if finds any data through the database. My question is how can I stop it if it finds any data? So there is no need to run again and again.

setInterval(function myalert() {
$.getJSON("handler.php?type=alert&callback=?&cookie="+ y, showAlert);
}, 7000);

on backend this is a part of the php

$alertGroup = mysql_fetch_array($alertQuery);
$json[] = array($title,$text);
echo $callback . "(" . json_encode($json)  . ")";

this is the showAlert

function showAlert(data) {
console.log(data[0][0]);
console.log(data[0][1]);
}

Use a named function and then clearInterval when data is found: http://stackoverflow.com/questions/109086/stop-setinterval-call-in-javascript — manonthemat, Apr 14 '16 at 20:34

score 1 · Answer 1 · answered Apr 14 '16 at 20:37

1

First of all, you have to register your setInterval into a variable to take control of it's instance, look:

var my_interval = setInterval(function myalert() {
$.getJSON("handler.php?type=alert&callback=?&cookie="+ y, showAlert);
}, 7000);

To stop a running timer you should use clearInterval in the instance, look:

clearInterval(my_interval);

answered Apr 14 '16 at 20:37

RPichioli

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thank you, but where to place the clearInterval? Inside the showAlert ? – EnexoOnoma Apr 14 '16 at 20:38

How to stop a function that runs every 7 seconds if it finds any data?

1 Answers1