Error while converting the String to float.(NumberFormatException)

Question

Can you tell me how to achieve this in android:

Transform a String into a float as in:

String temp="1,000,00"

to

float f=100f

I had already gone through links. Getting this exception :

java.lang.NumberFormatException: Invalid float: ""

check if string is empty using if(!TextUtils.isEmpty("your string") do something — Raghunandan, Apr 15 '16 at 10:39
please show your code. The string is empty, there must an issue anywhere.... — Opiatefuchs, Apr 15 '16 at 10:41

score 3 · Accepted Answer · answered Apr 15 '16 at 10:34

3

Have you tried like this:

String s = "100";
float f = Float.parseFloat(s);

and make sure that the String you are parsing is indeed a float and is not null or empty

answered Apr 15 '16 at 10:34

yes it gives me value f=100.0..i want the value to be f=100f – Sagar Gangawane Apr 15 '16 at 10:39
1

Why would you want that? – Nongthonbam Tonthoi Apr 15 '16 at 10:39
1

Maybe OP want to format that string so it will look like float :D – edasssus Apr 15 '16 at 11:08
1

@SagarGangawane `100f` is technically the same as `100.0`. `100f` is just a way of telling the compiler this is a `float` not and `int` for instance. – Alexander Suraphel Apr 15 '16 at 11:11
thanks for your reply but the method is not accepting the value It gives me exception as mentioned. – Sagar Gangawane Apr 15 '16 at 11:17

score 0 · Answer 2 · answered Apr 15 '16 at 10:35

0

You should be using the Float class's parseFloat method.

It sounds like the problem is with the actual string you are using though - can you post that?

answered Apr 15 '16 at 10:35

Martin Milan

for (String y:years) { float f = Float.parseFloat(y); Log.e(TAG,"Value of float \n"+ f + "Value of String "+ y); } – Sagar Gangawane Apr 15 '16 at 10:45
post it as a part of your question please, not as a comment... – Opiatefuchs Apr 15 '16 at 10:57
and what (using a debugger) is in "y" at this point? – Martin Milan Apr 18 '16 at 08:49

score 0 · Answer 3 · answered Apr 15 '16 at 10:36

0

Use the Float class.

// String to Float 
float temp = Float.parseFloat("100f");

// Float to String: 
String str = Float.toString(100.0f);

answered Apr 15 '16 at 10:36

Diyarbakir

3 Answers3