Broadcost massage in NodeJS

Question

When I broadcast message sender client also get notification from NodeJs here is my code, any chance why send get notification

socket.on('Room', function(data) {
   console.log(' Room : '+data);
   socket.broadcast.emit('Room', {'Room': 'Room'});
});

yes, the sender client will receive it too because he is in the same room — Jairo Malanay, Apr 15 '16 at 15:59
you can send the id of the sender and handle it in the frontend.. maybe they got better suggestion — Jairo Malanay, Apr 15 '16 at 16:08

score 1 · Answer 1 · edited May 23 '17 at 12:31

1

Send response to all clients except sender (Socket.io)

// sending to all clients in 'game' room(channel) except sender
socket.broadcast.to('game').emit('message', 'nice game');

edited May 23 '17 at 12:31

Community

1
1

answered Apr 15 '16 at 17:12

danday74

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Yes, but be aware that there's a bug(?) with broadcast.to().emit()

var transport = socket.broadcast.to('room');
setTimeout(function(){

 // this works, will send to all expect the socket
 socket.broadcast.to('room).emit(e, data);
 // this doesnt work. bug?
 transport.emit(e, data);
}, 
1000);

– Julius Loa Jun 22 '16 at 09:35

Broadcost massage in NodeJS

1 Answers1