PHP - $x=0 -- Why is it passing off as being equal to 1?

Question

I have a few lines of code

$case=0;
file_put_contents("text.txt", $case, FILE_APPEND);
if ($case = 1)
{
    $message['a']="co"; 
}
if ($case = 0)
{
    $message['a']="to";
}
echo $message['a'];

It will echo "co". Why is this? The file_put contents puts "0". However the if statement thinks it is 1 for some reason...

You need to use ` == ` for both if statements – larsAnders Apr 17 '16 at 05:18 — larsAnders, Apr 17 '16 at 05:18

score 0 · Answer 1 · answered Apr 17 '16 at 05:18

you have to use the comparison operator "==" when comparing values: otherwise you are assigning values (in this case you were assigning $case to be 1 and then the message was "co".

$case=0;
    file_put_contents("text.txt", $case, FILE_APPEND);
    if ($case == 1)
    {
        $message['a']="co"; 
    }
    if ($case == 0)
    {
        $message['a']="to";
    }
    echo $message['a'];

score 0 · Accepted Answer · answered Apr 17 '16 at 05:18

0

You are doing wrong in if condition. You doing assign instead of comparison.
So here is the solution.

$case=0;
file_put_contents("text.txt", $case, FILE_APPEND);
if ($case == 1)
{
    $message['a']="co"; 
}
if ($case == 0)
{
    $message['a']="to";
}
echo $message['a'];

answered Apr 17 '16 at 05:18

Md. Sahadat Hossain

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ha ha ha - its a race to get the same answer out @Md. Sahadat Hossain :)) – gavgrif Apr 17 '16 at 05:21
You have no idea how mad you just made me. I've been freaking getting so pissed off with the constant thoughts. "WHY YOU NO WORKS?!?!?!?!" Well, turns out I'm an idiot. – Amath1an Apr 17 '16 at 05:36

PHP - $x=0 -- Why is it passing off as being equal to 1?

2 Answers2