'ListViewItem' does not contain a contructor that takes 1 argument, Windows phone c#

Question

Hi I am trying to add items to a listview but get the following error, 'ListViewItem' does not contain a constructor that takes 1 argument. I am getting the error here new ListViewItem(row); I am using Windows phone 8.1 in c#.

protected override void OnNavigatedTo(NavigationEventArgs e)
    {
        int totalq = int.Parse(textBox.Text) + app.vanilla;
        textBox.Text = totalq.ToString();
        double totalvanilla = Convert.ToDouble(totalq)* 1.50;
        textBox_Copy.Text = totalvanilla.ToString();
        //listBox.Items.Add(totalq.ToString() + "Vanilla");

        string[] row = { totalq.ToString(),"vanilla" };
        var listViewItem = new ListViewItem(row); 

        listView.Items.Add(listViewItem);


    }

please add your listview xaml code, where you want to use the listview data — reza.cse08, Apr 19 '16 at 04:14

score 3 · Answer 1 · edited May 23 '17 at 12:32

I think you're the System.Windows.Forms.ListViewItem (which has a constructor for taking a string array) with the xaml-based System.Windows.Controls.ListViewItem.

You'd use the latter in another way:

XAML:

<ListView x:Name="listView">
    <ListView.View>
        <GridView>
            <GridViewColumn Header="Name" DisplayMemberBinding="{Binding Path=Name}"/>
            <GridViewColumn Header="Qunatity" DisplayMemberBinding="{Binding Path=Quantity}"/>
        </GridView>
    </ListView.View>
</ListView>

Code:

int totalq = 23;
var row = new { Quantity = totalq, Name = "vanilla" };

listView.Items.Add(row);

Edit:

If GridView isn't an option for you and you want to / have to put everything in place yourself, you can use following approach (based on this answer):

<ListView x:Name="listView">
    <ListView.ItemTemplate>
        <DataTemplate>
            <Grid VerticalAlignment="Center">
                <Grid.ColumnDefinitions>
                    <ColumnDefinition Width="50" />
                    <ColumnDefinition Width="*" />
                </Grid.ColumnDefinitions>

                <TextBlock Grid.Column="0" Text="{Binding Quantity}" />
                <TextBlock Grid.Column="1" Text="{Binding Name}" />
            </Grid>
        </DataTemplate>
    </ListView.ItemTemplate>
</ListView>

Gridview column does not exist in windows phone 8.1. It shows an error when I use this method. — samuel, Apr 17 '16 at 17:18

score 0 · Answer 2 · answered Apr 17 '16 at 10:24

0

You are sending string as parameters to listviewtem.ListViewItem has content property ,

Do like this

listView.Items.Add(new ListViewItem{Content = whateveryourstring});

answered Apr 17 '16 at 10:24

Sajeetharan

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It gives me system.string, any idea why? – samuel Apr 17 '16 at 10:53
When I run the program. – samuel Apr 17 '16 at 10:53

reza.cse08 · Answer 3 · 2016-04-19T04:44:05.253

I think you need to add a class with the property that you want to show at view. Like this.

public class ListModel {
    public string TotalQuantity { set; get; }
    public string Name { set; get; }
}

Then try this XAML

xmlns:toolkit="clr-namespace:Microsoft.Phone.Controls;assembly=Microsoft.Phone.Controls.Toolkit"

<toolkit:ListView Name="listView">
    <toolkit:ListView.ItemTemplate>
       <DataTemplate>
           <Grid>
               <Grid.ColumnDefinitions>
                   <ColumnDefinition Width="100" />
                   <ColumnDefinition Width="*" />
                </Grid.ColumnDefinitions>                       
                <TextBlock  Text="{Binding TotalQuantity}" />
                <TextBlock Grid.Column="1" Text="{Binding Name}" />
           </Grid>
       </DataTemplate>
   </toolkit:ListView.ItemTemplate>
</toolkit:ListView>

Finaly add the itemsource for list view

int totalq = int.Parse("3") + 2;
textBox.Text = totalq.ToString();
double totalvanilla = Convert.ToDouble(totalq) * 1.50;
textBox_Copy.Text = totalvanilla.ToString();
listBox.Items.Add(totalq.ToString() + "Vanilla");

ListViewItems = new ObservableCollection<ListModel>();
ListViewItems.Add(new ListModel()
{
    TotalQuantity = totalq.ToString(),
     Name = "vanilla"
});
listView.ItemsSource = ListViewItems;

'ListViewItem' does not contain a contructor that takes 1 argument, Windows phone c#

3 Answers3