Poorly formatted json parsing

Question

I use code above to parse JSON in a try-catch.

        JSONArray jsonRootObject = new JSONArray(text);
        JSONArray jsonArray = jsonRootObject.optJSONArray(2);

        name = jsonArray.toString();
        Toast.makeText(MainActivity.this, name, Toast.LENGTH_LONG).show();

I use 2 as index in code below, because I would get values from candidates. I think, that is strange, because there isn't key-value pairs in array. I would like to get only the first key from this array (In this example subtest1.), its value isn't make sense.

{
    "images": [
    {
        "time": 2.86091,
        "transaction":
        {
            "status": "Complete",
            "subject": "test2",
            "confidence": 0.77,
            "gallery_name": "gallerytest1",
        },
        "candidates": [
        {
          "subtest1": "0.802138030529022",
          "enrollment_timestamp": "1416850761"
        },
        {
          "elizabeth": "0.802138030529022",
          "enrollment_timestamp": "1417207485"
        },
        {
          "elizabeth": "0.777253568172455",
          "enrollment_timestamp": "1416518415"
        },
        {
          "elizabeth": "0.777253568172455",
          "enrollment_timestamp": "1416431816"
        }
        ]
    } ]
}

What's your problem? your question is quit clear. make it clear first — M D, Apr 18 '16 at 06:47
You seem to confuse Json Arrays and Objects. In Objects you access the properties by name, in Arrays you access the elements by number. — Henry, Apr 18 '16 at 06:49
What you want from your candidates array? The first element only? — Shafayat Mamun, Apr 18 '16 at 06:50

Ravi Theja · Answer 1 · 2016-04-18T07:21:09.143

1

your parser should be like.FYI JSONArray does not have key-value pairs but JSONObject does.

JSONObject root = new JSONObject(text);
JSONArray jarray = root.optJSONArray("images);
if(jarray != null){
   JSONObject jObject = jarray.optJSONObject(0);
   if(jObject != null){
      JSONArray candidates = jObject.optJSONArray("candidates");
      JSONObject jObj = jarray.optJSONObject(0);
      if(jObj != null){
          String subTest =  jObj.optString("subtest1");
      }
   }
}

edited Apr 18 '16 at 07:21

answered Apr 18 '16 at 06:50

Ravi Theja

3,371
1
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Same thing... I cannot say. that I need `subtest1`, because it is vary on request, this is not a fix name. – plaidshirt Apr 18 '16 at 07:10
jobj.keys() you wil all the keys in the first jsonObject.You can loop for all the json Objects in jsonarray. – Ravi Theja Apr 18 '16 at 07:20
`subTest` string is also empty. I have tried to use my string instead of subtest1. – plaidshirt Apr 20 '16 at 05:48

Shafayat Mamun · Accepted Answer · 2016-04-18T10:21:40.917

1

Try this and see if it solves your problem

 JSONArray CandidatesArr = new JSONArray(jsonRootObject.getString("candidates"));
        JSONObject CandidatesOBJ = CandidatesArr.getJSONObject(0);
String name=CandidatesOBJ.getString("subtest1");

Edit

To check if your key subset1 exists or not try the following code:

String name=""
    if(CandidatesOBJ.has("subtest1")){
name=CandidatesOBJ.getString("subtest1");
    }

edited Apr 18 '16 at 10:21

answered Apr 18 '16 at 06:53

Shafayat Mamun

439
1
6
22

I cannot say. that I need `subtest1`, because it is vary on request. So, it isn't fix value. In fact I would like to get `subtest1` as the value, because I can't know it in a response. – plaidshirt Apr 18 '16 at 07:08
So you want to check if subset1 exists in your object and get the value of subset1? Or you want subset1 as the value? like the name of the keys(subset1/elizabeth) ? – Shafayat Mamun Apr 18 '16 at 07:13
See this answer [link]("http://stackoverflow.com/questions/13573913/android-jsonobject-how-can-i-loop-through-a-flat-json-object-to-get-each-key-a") – Shafayat Mamun Apr 18 '16 at 07:26
I would like to check, if like subset1 is exists or not. – plaidshirt Apr 18 '16 at 10:05
Updated my code. Please check if this was the thing that you were looking for. – Shafayat Mamun Apr 18 '16 at 10:22
It says: `org.json.JSONException: No value for candidates` – plaidshirt Apr 18 '16 at 20:44

Poorly formatted json parsing

2 Answers2