Get substring after first space and before first instance of a special character?

Question

I am successfully returning a substring before the first instance of a space in a string:

var str = "test1 test2 test3 (test4)";
var str_BeforeSpace = str.substr(0,str.indexOf(' '));
// returns "test1"

What I'm trying to do next is return a substring that exists after the first space and before the first instance of a "(". In this example, the desired substring is "test2 test3" (with no trailing spaces) ...

score 2 · Answer 1 · edited May 23 '17 at 12:16

2

Not much different:

str.substring(str.indexOf(' ') + 1, str.indexOf('('));

If you want to trim leading and trailing spaces, see Trim string in JavaScript? .

edited May 23 '17 at 12:16

Community

1
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answered Apr 20 '16 at 15:18

Felix Kling

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In an example string "John B. Doe (Class of 2016)", this function is returning "B. Doe (Class" – faalbane Apr 20 '16 at 15:22
you might want to make it `a = str.indexOf(' '), b = str.indexOf('(', a)` – Bergi Apr 20 '16 at 15:22
1

Surely you meant `slice`, not `substr`? – Bergi Apr 20 '16 at 15:23
@Bergi: I can never remember whether `substr` or `substring` take the end index. So I guess I mean `substring`. I guess `slice` works too. – Felix Kling Apr 20 '16 at 16:08
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I just always use `slice`. It works the same on arrays :-) – Bergi Apr 20 '16 at 16:10

Get substring after first space and before first instance of a special character?

1 Answers1