Python - Count number of integers in a string?

Question

I'm just getting back into python and was wondering if there is an easy way to return the number of integers that exist in a given string.

For example if I had a list,

['1 5','2 10 23','214 33 1']

iterating through each item in the list and finding the number of integers would return 2, 3, and 3, respectively.

The only thing I can think of would be to have a 2-dimensional list, where each item in the main list is another list that holds the separate numbers, and then I could call len() on each secondary list. Is there an easier way?

You need to show what you tried first. – octopusgrabbus Apr 20 '16 at 18:41 — octopusgrabbus, Apr 20 '16 at 18:41

score 1 · Accepted Answer · answered Apr 20 '16 at 18:46

1

Just use a list comprehension. This requires that integers are split by a space ' ' in your list of strings.

data = ['1 5','2 10 23','214 33 1']
int_per_string = [len(x.split(' ')) for x in data]

Returns:

Out[8]:[2, 3, 3]

answered Apr 20 '16 at 18:46

Nathan Clement

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Thats perfect, thank you! I forgot how powerful lists are in python. – johnsmith101 Apr 20 '16 at 19:05

score 0 · Answer 2 · answered Apr 20 '16 at 19:03

According to the example you kept, for each item in your list they were separated with spaces. So you can try using .isdigit()

    numCount=[]
    for item in list:
        index=0
        sublist = item.split()
        for subitem in sublist:
            if subitem.isdigit():
                index +=1
        numCount.append(index)
    print(numCount)

I hope this will help you. You can also use subitem.isalnum() instead of subitem.isdigit() if you want to check for a number which is included along with a string.

Thank you.

Python - Count number of integers in a string?

2 Answers2