1

I'm trying to send a file to an API and then get the response - a CSV file (I've seen different posts about it but I couldn't make it work)

The examples in the documentation use httpie 

http --timeout 600 -f POST http://api-adresse.data.gouv.fr/search/csv/ data@path/to/file.csv

but when I'm using requests, I get an 400 Bad Request 

path = '/myfile.csv'
url = 'http://api-adresse.data.gouv.fr/search/csv/'
files = {'file': open(path, 'rb')}
res = requests.post(url, data=files)
Martijn Pieters
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kwn
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1 Answers1

5

You need to specify files keyword argument, not data to post multipart/form-data request.

And the key should match: file -> data

path = 'path/to/file.csv'
url = 'http://api-adresse.data.gouv.fr/search/csv/'
files = {'data': open(path, 'rb')}
#        ^^^^^^
res = requests.post(url, files=files)
#                        ^^^^^
falsetru
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